![]() PowerScore students will immediately recognize the Pythagorean Triple 15:20:25 (a multiple of the 3:4:5 triangle). Question 8 Test 2, Second QR Section (version 2) A bush will be dug up and then planted again. Quantity B (2) is greater than Quantity A (1.19). RECORD what you know: Volume = 15 Radius = 2 Volume = �r2h 15 = �22h → 15 = 3.14(4)h QA: The height of the cylinder QB: 2 inches Geometry: Geometric Solids 1. Question 7 Test 2, Second QR Section (version 2) A right circular cylinder with radius 2 inches. So the standard deviation in B must be greater than the standard deviation in A. Simply put: when a data set clusters towards the middle (towards the average) standard deviation is less than when a data set has more outliers, with clusters at the ends (away from the average). So if you imagine these two data sets as bell curves, then in A you have the largest group in the middle at the average of 30 (standard type bell curve), while in B you have the opposite: the large groups are at the extremes of 10 and 50 and not at the average of 30 (an inverse bell curve of sorts, almost like a parabola), meaning the deviation from the standard (the central tendency we call “average”) is going to be much higher in B. This means the average is immediately right in the middle-both distributions have an average of 30. This is also true in Distribution B: the frequency in 10 and 50 is equal as is the frequency in 20 and 40. For example, in Distribution A, the frequency of 10 and 50 is the same, and the frequency of 20 and 40 is the same. ![]() In both graphs, there is symmetry in each set of consecutive terms. Standard deviation is higher when there are more elements far from the average. Instead, you can solve this one simply by analyzing the data. This is a classic GRE case of a standard deviation question where actually trying to calculate values is a time-sucking trap. QA: The standard deviation of distribution A QB: The standard deviation of distribution B Data Analysis: Standard Deviation Answer: Quantity B is greater 1. Question 6 Test 2, Second QR Section (version 2) The frequency of distributions shown above. Thus, the relationship cannot be determined. The presence of absolute value symbols should make us want to SUPPLY negative numbers because of the special properties of absolue value. SUPPLY numbers for x and y: x = 3, y = 1 | x + y | → | x – y | → Question 5 Test 2, Second QR Section (version 2) x>y QA: | x + y | QB: | x – y | Algebra: Absolute Value Answer: The relationship cannot be determined 1. In this case, Quantity B is greater.īut what if x were at the other extreme of the range, such as x = 48? If we keep y = 1, that would mean that 40% of the numbers were between 0 and 1 and the next 20% were between 1 and 48 (and the remaining 40% were between 48 and 50). That would mean 40% of the numbers are between 0 and 1, and another 20% are between 1 and 2 to satisfy both y = 1 and x = 2. How can that be possible? It works if you consider there are an infinite number of numbers between 0 and 2 when you use decimals. That means that over 60 percent of the numbers are less than 2. SUPPLY numbers for x and y, using numbers at the extreme ends of the range.įor example, say that x = 2. QA: x – y QB: 20 Arithmetic: Percent Answer: The relationship cannot be determined 1. Question 4 Test 2, Second QR Section (version 2) T is a list of 100 different numbers that are greater than. Since t is greater, Quantity B is greater. QA: s QB: t Arithmetic: PercentĤ percent of s is equal to 3 percent of t 0.04 × s = 0.03 × t 0.04s = 0.03t s = 0.75t ![]() Question 3 Test 2, Second QR Section (version 2) 4 percent of s is equal to. The least integer in set X that is also in set Y is 11. There are four numbers that are common to both sets: 11, 12, 13, 14 Set X: 2. ![]() QB: 11 Answer: The two quantities are equalġ. QA: The least integer in set X that is also in set Y Arithmetic: Number Properties Question 2 Test 2, Second QR Section (version 2) X is the set of all integers less than. If you have a hard time understanding this, DIAGRAM the question and SUPPLY numbers for r and t. When multiplying numbers, a negative times a positive is always negative, so the product will always be less than 0. If 0 is between r and t, one of the numbers will always be negative and the other will always be positive. QA: The product of r and t QB: 0 Arithmetic: Number Linesġ. Question 1 Test 2, Second QR Section (version 2) The number 0 is between the two nonzero.
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